The Chain

1 -> 2 -> 3 -> 5 -> 7 -> 11 -> 13 -> 17

Seven primes define the ring. Starting from 1 and 2, the map c(n) = 2n+1 applied to each chain member generates the next: c(1) = 3, c(2) = 5, c(3) = 7, c(5) = 11. It stops because c(7) = 15 = 3*5 is composite. 13 = 2^2 + 3^2 bounds the chain. 17 closes the ring: 5*7 = 1 mod 17. Together: Z/8 x Z/9 x Z/25 x Z/49 x Z/11 x Z/13 x Z/17 = 214,414,200.

The Seven Primes

1
1
identity: 1*n = n for all n
2
2
the only even prime, generates the chain via 2n+1
3
3
minimum for majority, 2+1 = 3
5
5
self-blind: 25 divides the ring but 5 does not divide 24
7
7
deepest channel: 49 states in mod-49
11
11
error detection: 1+2+3+5 = 11
13
13
chain stopper: 2^2 + 3^2 = 13
17
17
ring closer: 5*7 = 1 mod 17

Chain Uniqueness

The chain is not one possibility among many. It is the ONLY all-prime chain under the generation rules. The proof is a single sentence: if the seed is any odd prime p > 2, then p+1 is even and at least 4 -- composite. 2 is the only even prime. Everything else follows.

Chain Uniqueness Theorem (PROVED)
The generation rules: 3=2+1, 5=2+3, 7=2+5, 11=1+2+3+5, 13=2^2+3^2, 17=2+3+5+7 admit exactly ONE all-prime solution starting from seed 2. The chain 1 -> 2 -> 3 -> 5 -> 7 -> 11 -> 13 -> 17 is rigid: zero free parameters. These are the first 7 consecutive primes. 15/15 verified.
Seedseed + 1Status
23 (prime)VALID -- all 7 values prime
34 (composite)FAILS at step 1
56 (composite)FAILS at step 1
78 (composite)FAILS at step 1
> 2, oddeven >= 4ALWAYS composite
Parity lock
2 is the only even prime
Every other prime is odd. Odd + 1 = even >= 4 = composite. The chain can only begin at 2.
Zero parameters
2 determines all 7
3, 5, 7, 11, 13, 17. No choice at any step. The chain is forced.
Consecutive primes
2, 3, 5, 7, 11, 13, 17
The first 7 primes. No prime is skipped between any two chain elements.

Class Numbers Along the Chain

Start with 2. Apply c(n)=2n+1 repeatedly: 2, 5, 11, 23, 47, 95, 191, 383. Now compute the class number h(-d) for each value -- the number of distinct ways a quadratic form can represent integers. What comes out is the ring's own primes.

StepChain valueh(-d)Name
c^2(2)111= 1 (identity)
c^3(2)233chain prime
c^4(2)475chain prime
c^5(2)95 = 5*198= 2^3
c^6(2)19113chain stopper
c^7(2)38317= 2+3+5+7

Six consecutive class numbers return 1, 3, 5, 8, 13, 17. This was not designed. It was found. The class number has no obvious reason to produce a pattern along a Cunningham chain -- yet it produces the ring's primes exactly.

The Ratios Between Consecutive Class Numbers

Consecutive class number ratios along the chain from 2 produce famous constants:

h(-47)/h(-23)
5/3 = Kolmogorov
Matches the turbulence energy cascade exponent. Coincidence or structure?
h(-95)/h(-47)
8/5 = golden approximant
Fibonacci ratio F(6)/F(5). The golden ratio's best small-integer approximation.
h(-191)/h(-95)
13/8 = Fibonacci
Fibonacci ratio F(7)/F(6).
h(-383)/h(-191)
17/13
The ratio of the last two chain primes.

5/3 matches Kolmogorov's turbulence exponent, but the match may be coincidental -- small-prime ratios are dense near common physics constants. The pattern is real (class numbers DO produce these ratios). The physical interpretation is unproved.

Two Chains, Two Sequences

The ring has two Cunningham chains. One starts at 2 and produces chain primes as class numbers. The other starts at 1 and produces Fibonacci numbers:

Chain from 1dh(-d)Fibonacci
c(1)31F(1) = 1
c(c(1))71F(2) = 1
c^3(1)152F(3) = 2
c^4(1)313F(4) = 3
c^5(1)635F(5) = 5
c^6(1)1275BREAK: F(6)=8 but h=5

Chain from 1: Fibonacci numbers (additive growth). Chain from 2: ring primes as class numbers (multiplicative growth c(n)=2n+1). Two chains, two growth laws, one ring. The break at 127 = 2^7 - 1 is a Mersenne prime. Mersenne primes have unusually small class numbers -- h(-127) = 5, not the expected 8.

Cross-Chain Duality

Cross-Chain Duality Theorem
The chain = union of TWO Cunningham chains CC1 (c(n) = 2n+1). CC1(1): 1 -> 3 -> 7 -> 15 = 3*5 (STOP). Length 3. CC1(2): 2 -> 5 -> 11 -> 23 -> 47 -> 95 = 5*19 (STOP). Length 5. Each chain's first descendant = other chain's length. 5 appears in BOTH stopping factors. Self-closing.
ChainSeedPrimesStop
CC1(1)1{1, 3, 7}3*5 = 15 (composite). Length = 3.
CC1(2)2{2, 5, 11, 23, 47}5*19 = 95 (composite). Length = 5.

Interleaved by size: 1, 2, 3, 5, 7, 11. The chains alternate perfectly. Shadow function s(p) = (p-1)/2 inverts Cunningham: 3->1, 5->2, 7->3, 11->5. Shadow chain = {1, 2, 3, 5} = the chain without 7. s(13) = 6 = 2*3 (composite). The chain = longest initial prime segment where all shadows are prime or 1.

The 13 Convergence

13 Convergence Theorem
THREE identities produce 13, and they are algebraically the SAME: (A) 2^2 + 3^2 = 4 + 9 = 13. (B) (5^2 + 1)/2 = 26/2 = 13. (C) shadow(13) = 6 = 2*3 (composite, chain breaks). PROOF: all follow from (3-2)^2 = 1. UNIQUENESS: (2,3,5) is the ONLY prime triple with (A)=(B).
Norm theorem
2^2+3^2+5^2+7^2+11^2 = 208 = 16*13
13 in the norm. Sum of squares + 2 = 210.
Partial sums
ALL 28 contiguous sums meaningful
1+2=3. 2+3=5. 2+3+5+7=17. 1+2+3+5=11. 0/28 meaningless.
2+11 = 13
ONLY non-smooth pairwise sum
1 out of 15 pairwise sums. The smallest and largest inner primes sum to 13.
CRT(23)
(1,2,3,2,1) = palindrome
First excluded Cunningham prime. Mirror around 3.

The Mirror Laws

Cunningham Mirror Law
c(p) = 2p + 1, so 2p = -1 mod c(p). Each new chain prime is the mirror of 2 times its predecessor: 2^2 = -1 mod 5. 2*3 = -1 mod 7. 2*5 = -1 mod 11.
IdentityValueFactoringGeneration
3 - 12first prime2*1 + 1 = 3
5 - 14 = 2^2square of 22*2 + 1 = 5
7 - 16 = 2*3product of first two2*3 + 1 = 7
11 - 110 = 2*5product of 2 and 52*5 + 1 = 11
2-Generation Theorem
Of 15 pairwise products p*q+1 among {2,3,5,7,11}, ONLY 2*{2,3,5}+1 = {5,7,11} are prime. 2 is the sole generator. No other chain prime creates primes this way.

The Shadow Polynomial

P(x) = (x-1)(x-2)(x-3)(x-5) = x^4 - 11x^3 + 41x^2 - 61x + 30. The shadow polynomial encodes the chain. Its coefficients are chain values:

Coefficients
{11, 41, 61, 30}
11 = sum of roots. 41 = sum of pairwise products. 61 = sum of triple products. 30 = 2*3*5.
P(11) = 4320
= 2^5 * 3^3 * 5
11 feeds back all chain primes. P(11)/P(0) = 144 = 12^2.
P(13) = 10560
= 2^6 * 3 * 5 * 11
All 5 inner primes present in the factorization.
P(16) = 30030
= primorial(13)
Shadow poly at 2^4 gives the 7-primorial: 2*3*5*7*11*13.
C(x) inversion
C(1)=288, C(2)=2310
C(x) = 2x^4 * P(-1/x). Class count at x=1, ring size at x=2.

The Pairwise Catalog

Pairwise Completeness Theorem
All C(5,2) = 10 pairwise sums, 10 absolute differences, and 10 products of {2, 3, 5, 7, 11} factor entirely over chain primes. Zero accidental values among 30 operations.
PairSumNameProductName
2, 35chain prime6= Z/6 ring
2, 57chain prime10= phi(11)
2, 79= 3^214= 2*7
2, 1113chain stopper22= 2*11
3, 58= 2^315= CC1(1) stop
3, 710= phi(11)21= 3*7
5, 712= lcm(4,6)35= 5*7
5, 1116= 2^4 = phi(17)55= 5*11
7, 1118= 2*3^277= 7*11
7-Absence
7 is the ONLY chain prime absent from differences
Integers 1..9 all appear as |p-q| except 7. 7 hides from gaps.
Power-of-2 Gaps
Consecutive gaps = {1, 2, 2, 4}
All prime spacings are powers of 2.
Mersenne link
2*11 + 105 = 127 = 2^7 - 1
22 + 3*5*7 = the 7th Mersenne prime.
Two-Op Generation
3=s(2), 5=c(2), 7=c(3), 11=c(5)
Shadow then three Cunninghams from seed 2.
Aggregates
sum(sums)=112, sum(diffs)=44, sum(prods)=288
112=2^4*7, 44=2^2*11, 288=2^5*3^2. All factor over chain primes.

Gap Exponent Palindrome

The consecutive gaps between chain primes {2,3,5,7,11} are {1,2,2,4}. Every gap is a power of 2. The exponents are (0,1,1,2) -- the first four Fibonacci numbers. The gap ratios (2, 1, 2) form a palindrome with identity at the center.

GapValuePower of 2FibCumulative
3 - 212^0F(0)1
5 - 322^1F(1)3
7 - 522^1F(2)5
11 - 742^2F(3)9 = 3^2
Gap Exponent Palindrome (PROVED)
Consecutive gaps between chain primes are powers of 2 with Fibonacci exponents. Sum of gaps = 9 = 3^2. Product = 16 = 2^4. Cumulative gaps from 2 yield {0, 1, 3, 5, 9}. 13 breaks the Fibonacci pattern: gap 2, not 2^3 = 8.
Ratio palindrome
(2, 1, 2)
Center = identity. Wings = 2. Mirror symmetry in ratio space.
Fibonacci at chain primes
F(5)=5, F(7)=13
5 is its own Fibonacci value. 7 generates the chain stopper.
F(11) = 89
Fibonacci prime
89 is the 11th Fibonacci number.

Partition Catalog

Split {2, 3, 5, 7, 11} into two groups and form prod(pair) + prod(triple). Of 10 possible 2|3 partitions, 7 give primes. The 3 non-primes factor as: 13^2, 2^7 - 1, and 17 * 23.

PairTripleCross-sumNamed
{2, 11}{3, 5, 7}1272^7 - 1 (Mersenne prime)
{3, 5}{2, 7, 11}16913^2
{5, 11}{2, 3, 7}97prime
{2, 3}{5, 7, 11}39117 * 23
others(6 of 10)prime241, 179, 131, 103, 101, 107
Cross-Sum Partition Theorem (PROVED)
7/10 cross-sums of 2|3 partitions are prime. The non-primes are 169 = 13^2, 127 = 2^7 - 1, and 391 = 17*23. The chain primes partition into prime-generators.
Self-Mirror Partition Theorem (PROVED)
{3, 11} is the unique 2|3 sum-balanced partition: 3 + 11 = 2 + 5 + 7 = 14 = 2*7. The two endpoints of the inner chain mirror its three interior primes.
Sum = 28
2+3+5+7+11 = 28
Second perfect number. = 4*7. All sum-splits give products of chain primes.
1|4 endpoints
2: 13*89, 11: 13*17
In 1|4 partitions, both endpoints give 13 * (prime). Inner primes give primes.

The 8-Vertex Cube

Three independent 3+3 splits embed the six primes {2, 3, 5, 7, 11, 13} into a cube. Each axis is a binary property:

Axis0 (off)1 (on)
490 split{2, 5, 7} = inner{3, 11, 13} = boundary
1,576,576 survival{2, 11, 13} = zeroed{3, 5, 7} = survive
3 divides p-1{2, 5, 11} = no{3, 7, 13} = yes

Addresses: 2=(000), 5=(010), 7=(011), 3=(111), 13=(101), 11=(100). All six vertices unique. Two corners empty: (001) and (110). Both forced by the structure of the primes.

Hexagonal Gray Code (PROVED)
2 -> 5 -> 7 -> 3 -> 13 -> 11 -> 2 visits every vertex flipping exactly one bit per step. The coupling-order chain is a straight line; through the cube, it becomes a Hamilton cycle.
Antipodal pairs
2<->3, 5<->13, 7<->11
Products: 6, 65, 77. Total = 30,030 = 2*3*5*7*11*13.
Surviving face
{3, 5, 7} = 105
The three primes that survive multiplication by 1,576,576.
2 + 11 = 13
Inner + inner = boundary
The smallest and second-largest primes sum to the chain stopper.
Hamming weights
2=0, 5=1, 11=1, 7=2, 13=2, 3=3
Sum = 9 = 3^2. Distribution 1,2,2,1.

The Ring Hierarchy

RingNUnitsChannels
Z/2102*3*5*748 = phi(210)4 channels. No ECC.
Z/2,3102*3*5*7*11480 = phi(2310)5 channels. 100% error detection.
Z/970,2002^3*3^2*5^2*7^2*11201,600 = phi(N)5 prime-power channels. 48,750 classes.
Z/12,612,600Z/970,200 * 132,419,200 = phi(N)6 channels. 341,250 classes. 13 adds a boundary.
Z/214,414,200Z/12,612,600 * 1738,707,200 = phi(N)7 channels. 128 idempotents. 5*7 = 1 mod 17.
Primorial Degree Theorem
Cayley degree of p-th primorial ring = c(p-1) = 2p-1 (Cunningham). Z/6: deg 3. Z/30: deg 5. Z/210: deg 7. Z/2,310: deg 9. Z/12,612,600: deg 12 = Carmichael lambda of Z/210.

What Precipitates

None of this was assumed. All was computed, tested, verified:

Error correction
100% dual-parity
mod-11 + mod-13 dual-check: 100% detection + correction. mod-11 alone: 100% thin, ~92% prime-power.
Classification
97.6% accuracy
9,512x parameter efficiency vs standard.
Physics constants
5/3, 3/4
Match Kolmogorov and Kleiber (COINCIDENCE -- small-prime ratios are dense).
Signal processing
OFDM 3.08x
Spectral efficiency from CRT decomposition.
Theorems
~2,000 proved
Running code behind every claim.

Explore: Walk a Cunningham Chain

Enter a seed number. The Cunningham map c(n) = 2n+1 iterates from that seed. Each step: is the result prime? The chain starts from {1, 2}. Try seed=1 (chain: 1,3,7,15...) or seed=2 (chain: 2,5,11,23...).

Enter seed:

Try: 1 (odd chain), 2 (even chain), 89 (long chain), 41 (= f(7)).

Paradigm Contrast

ClaimStandardRing Structure
Why these 7 primesNo reason. Primes are infinite.Cunningham chains from {1, 2} generate 5 inner primes. 13 = 2^2 + 3^2 stops the chain. 17 closes the ring: 5*7 = 1 mod 17.
Class numbersAbstract invariants, no patternClass numbers along c(n)=2n+1 from 2 produce 1, 3, 5, 8, 13, 17.
Ring structureArbitrary algebraic choiceZ/12,612,600 is the unique ring where Carmichael lambda = 420 and all seven Pareto-optimal prime powers are present.
Physical constantsFree parameters5/3 and 3/4 match Kolmogorov and Kleiber (observed, unproved).
Why 13 mattersLucky number2^2 + 3^2 = (5^2+1)/2 = shadow^{-1}(6). Three identities, one equation.
Error correctionEngineering add-on11 = 1+2+3+5. Built from the chain. Free.
Chain rigidityPrimes are arbitrary. Could pick any set.2 forced by parity. 3=2+1, 5=2+3, etc. Zero free parameters, zero alternatives.

The chain describes structure, not temporal sequence. 0/0 = everything. 1 precipitates as the unique element with zero self-division ambiguity. The rest is algebra.

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