The Smooth Census

13 = GATE: the universal boundary of 11-smoothness in classical sequences

What others see vs. what the axiom shows

Standard view

Various classical sequences (Fibonacci, sigma, partitions, etc.) each have finitely many "smooth" initial values. The counts seem unrelated: 5, 6, 8, 11, 12. Just scattered facts from analytic number theory.

Through the axiom

Every count is an axiom constant: E=5, D*K=6, D^3=8, L=11, D^2*K=12. The blocker is always 13=GATE. Row 13 of Pascal's triangle spells the complete axiom chain as its smooth run lengths vary.

The Binomial Smooth Theorem

An integer is 11-smooth if its only prime factors come from {2, 3, 5, 7, 11}.

For n ≤ 12, the factorial n! contains only primes ≤ 11. So C(n, k) = n! / (k! (n-k)!) is a ratio of 11-smooth numbers, hence 11-smooth. But at n = 13, the prime 13 enters 13! and divides C(13, k) for all 1 ≤ k ≤ 12 (by Lucas' theorem: 13 is prime, so 13 | C(13, k) whenever 0 < k < 13).

THEOREM: C(n, k) is 11-smooth for all k ≤ n ≤ 12. At n = 13, every C(13, k) = 13 × (smooth number). The GATE is the sole intruder.

The smooth run length at depth k (counting values from n = k to n = 12) is:

run(k) = GATE - k = 13 - k

As k varies from 1 to 12, this traverses the complete axiom vocabulary:

kRun = 13-kAxiom nameC(13,k)= 13 ×
112D2*K131 = sigma
211L786 = D*K
310D*E28622 = D*L
49K271555 = E*L
58D3128799 = K2*L
67b1716132 = D2*K*L
76D*K1716132 = D2*K*L
85E128799 = K2*L
94D271555 = E*L
103K28622 = D*L
112D786 = D*K
121sigma131 = sigma

The run lengths {12, 11, 10, 9, 8, 7, 6, 5, 4, 3, 2, 1} = the full chain from D2*K down to sigma. The row C(13, k)/13 is PALINDROMIC and every quotient is 11-smooth.

Pascal's triangle is smooth below the GATE. Above it, 13 contaminates everything.

Pascal's Triangle: The Smooth Boundary

Rows 1-14. Gold = 11-smooth. Red = contains prime > 11. Row 13 = the GATE wall.

The Independent Smooth Census

Classical sequences whose smooth runs are NOT explained by binomial coefficients. Each has an initial 11-smooth run whose length is an axiom constant, blocked by 13 = GATE:

SequenceRun= AxiomFails atFirst non-smooth valueBlocker
Bernoulli denom B2n5En=6=D*K2730 = 2*3*5*7*1313
Fibonacci F(n)6D*Kn=7=bF(7) = 1313
Catalan Cn6D*Kn=7=b429 = 3*11*1313
Sum of divisors sigma(n)8D3n=9=K2sigma(9) = 1313
Triangle T(n)=n(n+1)/211Ln=12=D2*K78 = 2*3*1313
Partition p(n)12D2*Kn=13=GATEp(13) = 101 (prime)101
Bell B(n)5En=5=EB(5) = 52 = 22*1313

In 6 of 7 sequences, 13 = GATE appears in the blocking VALUE. In partitions, 13 is the blocking POSITION (p(13) is the first non-smooth partition number). The GATE blocks either way.

The Non-Trivial Coincidences

Triangle numbers are binomial: T(n) = C(n+1, 2). Their smoothness follows from the Binomial Theorem. But these do NOT follow from binomials:

sigma(9) = 13 (sum of divisors)

sigma(9) = 1 + 3 + 9 = 13. The divisor sum of K2 = 9 happens to EQUAL the gate prime. No binomial coefficient is involved. This is a number-theoretic coincidence: the divisors of the stop number sum to the gate.

F(7) = 13 (Fibonacci)

The b-th Fibonacci number is the GATE prime. The Fibonacci recurrence F(n) = F(n-1) + F(n-2) has no connection to 13 except that the cumulative additions hit 13 at exactly n = b = 7. Equivalently: F(b) = GATE.

B(5) = 52 = 4 * 13 (Bell numbers)

The E-th Bell number (counting partitions of a 5-element set) contains 13. Set partitions know about the GATE through the observer.

p(13) = 101 (partition function)

The GATE-th partition number is prime (101). The smooth run breaks at the GATE position itself. 101 is not a standard intruder, but CRT(101) = (E, D, sigma, K, D) = all axiom elements.

The Smooth Ladder

Ordering by run length, the sequences form a ladder from E = 5 to D2*K = 12. Each rung is an axiom constant, each gap is one step along the chain:

5
E
Bernoulli, Bell
6
D*K
Fibonacci, Catalan
8
D3
sigma(n)
11
L
Triangle
12
D2*K
Partition

Gaps: 6-5=1=sigma. 8-6=2=D. 11-8=3=K. 12-11=1=sigma. The gaps themselves are axiom constants.

Combined with the Binomial Theorem (which fills ALL values 1..12), the axiom's smoothness vocabulary is COMPLETE. Every integer from 1 to 12 appears as a smooth run length, and every one names an axiom constant.

Why 13 Is the Wall

13 = GATE = D2 + K2 is the smallest prime larger than L = 11. Since 11-smooth means "primes ≤ 11 only," the first possible intruder IS 13. What's remarkable is not that 13 blocks — that's inevitable — but HOW it enters each sequence:

SequenceHow 13 enters
Bernoulli B12von Staudt-Clausen: (p-1)|12, so p=13 enters since 12|12
FibonacciCumulative addition: 1,1,2,3,5,8,13. Hits 13 at step b=7
CatalanC(14,7)/8 = 429. 14! introduces 13, division by 8 doesn't remove it
sigma(n)1+3+9 = 13. Divisors of K2 = 9 sum to GATE
TriangleT(12) = 12*13/2. Factor 13 appears directly at n+1=13
Partitionp(13) = 101 (prime). GATE position, not GATE value
Bell52 = 4*13. Accumulated through Stirling numbers

Each entry mechanism is independent. Divisor sums, recurrences, combinatorial products, von Staudt-Clausen — all different mathematics, same wall.

Smooth Run Explorer

Compute the initial 11-smooth run of a sequence:

Number Theory Thread

The Smooth Census connects to:

The Last Smooth Pair - (2400, 2401) = where consecutive smoothness ends. Same Stormer bound limits the shadow quartet.

The Partition Function - p(n) smooth zone: exactly D2*K = 12 values. GATE at 13.

The Universal Boundary - 8 intruder primes, all generated by 3 axiom maps. 13 = GATE is the first.

Shadow Evaluations - L = 11 smooth quartets of the shadow polynomial. Same L from a different function.

The Two Chains - Cunningham chains generate the axiom. shadow(13) = 6 = D*K (composite, chain stops).

The Bernoulli Connection - Bernoulli denominators: E = 5 smooth, 13 enters via von Staudt-Clausen.

The Fano-E8 Bridge - Eisenstein smoothness: D4 = 16 smooth divisor sums in E8 theta series.

Binomial Smooth Theorem: proved S716. Independent Smooth Census: verified S716. Seven classical sequences, seven axiom-constant run lengths, one wall: 13 = GATE. Return to hub