Stormer's theorem (1897): finitely many consecutive pairs where both are 11-smooth. The LARGEST such pair is (2400, 2401). Their CRT decompositions reveal zero-trading: D and E channels empty on one side, b channel empties on the other. Smoothness ends when depth absorbs everything.
2400 = 2^5 * 3 * 5^2 = D^5 * K * E^2. 2401 = 7^4 = b^4. Their CRT decompositions reveal which channels carry zeros:
| Channel | 2400 | 2401 | Trade |
|---|---|---|---|
| D (mod 8) | 0 (ZERO) | 1 = sigma | D exits |
| K (mod 9) | 6 = D*K | 7 = b | neutral |
| E (mod 25) | 0 (ZERO) | 1 = sigma | E exits |
| b (mod 49) | 48 = b^2-1 | 0 (ZERO) | b enters |
| L (mod 11) | 2 = D | 3 = K | neutral |
2400 has zeros in D and E channels. 2401 has zero in b channel. The zeros TRADE: D*E yield to b. Bridge and observer step aside. Depth stands alone.
When 2400 occupies D and E, it fills b's channel to the brim: 48 = b^2 - 1. One step later, b takes over: its channel drops to 0, and D and E reset to sigma = 1.
Every consecutive smooth pair trades zeros (since gcd(n,n+1) = 1, their prime factors are disjoint). The larger pairs show increasingly dramatic trades:
| n | n+1 | Factorization | Zero Trade |
|---|---|---|---|
| 8 | 9 | D^3, K^2 | D -> K |
| 48 | 49 | D^4*K, b^2 | D*K -> b |
| 80 | 81 | D^4*E, K^4 | D*E -> K |
| 120 | 121 | D^3*K*E, L^2 | D*K*E -> L |
| 224 | 225 | D^5*b, K^2*E^2 | D*b -> K*E |
| 384 | 385 | D^7*K, E*b*L | D*K -> E*b*L |
| 2400 | 2401 | D^5*K*E^2, b^4 | D*K*E -> b (FINAL) |
The final pair is the most extreme: three primes on one side, one on the other. Depth absorbs bridge, closure, and observer. Only L stays neutral (never zeros in either).
In the last smooth pair, 2401 = b^4 is a pure power of a SINGLE axiom prime. All other primes (D, K, E) appear in 2400. The protector L divides neither.
| Aspect | Standard view | Through the axiom |
|---|---|---|
| The pair | 2400 and 2401 are consecutive integers. Stormer 1897 curiosity | CRT zeros TRADE: D*E yield to b. Structural, not accidental |
| Why last? | Analytic bound from Pell equations | b^3+1 blocked by Heegner 43. Only b^4 finds smooth neighbor |
| Sum | 4801 is prime, no further significance | CRT shows traded channels neutralized to sigma. Sum remembers the trade |
| L channel | 11 divides neither -- unremarkable | Protector stays neutral: shields but never participates in trades |
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