The Pell Twins

7 = 9 - 2 11 = 9 + 2

Two chain primes frame 3^2 = 9 from below and above. Both solve the Pell equation x^2 - p*y^2 = 1 with the same fundamental y = 3. Separated by 4 = 2*2, centered on the chain's stop value 9. And all five chain primes {2, 3, 5, 7, 11} have 11-smooth Pell coordinates.

The Twin Solutions

p = 7
8^2 - 7*3^2 = 64 - 63 = 1
x = 8 = 2^3. y = 3. Both coordinates are chain primes or prime powers.
p = 11
10^2 - 11*3^2 = 100 - 99 = 1
x = 10 = 2*5. y = 3. Again, both coordinates factor into chain primes.

The x-values: 8 = 2^3 and 10 = 2*5. Their sum: 8 + 10 = 18 = 2*3^2 = 7 + 11 (the twin sum). Their product: 80 = 2^4*5.

All Five Chain Primes

All five chain primes {2, 3, 5, 7, 11} have Pell solutions with 11-smooth coordinates:

Prime pxyCheck
2329 - 2*4 = 1
3214 - 3*1 = 1
59 = 3^24 = 2^281 - 5*16 = 1
78 = 2^3364 - 7*9 = 1
1110 = 2*53100 - 11*9 = 1
Sum(x)
3+2+9+8+10 = 32 = 2^5
The number of idempotents in Z/970,200 (five prime factors -> 2^5).
Sum(y)
2+1+4+3+3 = 13
= 2^2 + 3^2. Where the Cunningham chain stops.
Sum(x-y)
1+1+5+5+7 = 19 = 5^2-5-1
= f(5), the polynomial evaluated at 5.
Prod(x)/Prod(y)
4320/72 = 60
= 2^2*3*5. All coordinates are 11-smooth.

Quadratic Character Split

The Pell twins create a natural split. The Legendre symbol (p/7) separates the chain primes:

Prime(p/7)ClassReason
2+1Quadratic residue7 = 9 - 2 (Pell twin)
3-1Non-residueNot a Pell twin of 7
5-1Non-residueNot a Pell twin of 7
11+1Quadratic residue11 - 4 = 7 (Pell twin)

The Pell twins {2, 11} are quadratic residues mod 7. The non-twins {3, 5} are non-residues. The Pell equation sorts the chain's primes into two families.

Cyclotomic Connection

Both twins arise as cyclotomic polynomials evaluated at 2:

PolynomialValueName
Phi_3(2) = 4+2+17Eisenstein cyclotomic
Phi_4(2) = 4+15Gaussian cyclotomic
Phi_10(2) = (2^5+1)/31110th cyclotomic at 2
Phi_12(2) = 16-4+11312th cyclotomic at 2
Cyclotomic-Pell Bridge
Phi_3(2) = 2^2+2+1 = 7. Rearranging: 2^6 = 7*3^2 + 1 = 64. The Pell equation 8^2 - 7*3^2 = 1 encodes the same algebraic identity as the cyclotomic evaluation. Twin cyclotomic indices: 3 and 10. Their sum = 13 = 2^2+3^2. Their product = 30 = 2*3*5.

Explore: Pell Solution Finder

Enter a non-square number d. Find the fundamental solution to x^2 - d*y^2 = 1. For chain primes {2, 3, 5, 7, 11}, all solutions have 11-smooth coordinates. Sum(x) = 32. Sum(y) = 13.

Find Pell solution for d:

Try: 2 (x=3,y=2), 3 (x=2,y=1), 5 (x=9,y=4), 7 (x=8,y=3), 11 (x=10,y=3). Also: 13, 23, 41.

Contrast Table

Pell equationsClassical Diophantine equations. Solutions for different d values are unrelated.7 and 11 are twin Pell solutions sharing y = 3. All five chain primes solve Pell with 11-smooth (x,y). The sums are 32, 13, and 19.7 and 11Just two primes that happen to be 4 apart.Symmetric around 3^2 = 9 (the chain's stop). Same Pell y-coordinate. Same cyclotomic generation through 2.Quadratic residues mod 7Standard number theory classification.The Pell twins sort the chain into two families: {2, 11} (residues, framing 9 from below and above) vs {3, 5} (non-residues).

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